3x+x^2-6.25=0

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Solution for 3x+x^2-6.25=0 equation: 



3x+x^2-6.25=0

a = 1; b = 3; c = -6.25;
Δ = b2-4ac
Δ = 32-4·1·(-6.25)
Δ = 34
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-\sqrt{34}}{2*1}=\frac{-3-\sqrt{34}}{2}
$


$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+\sqrt{34}}{2*1}=\frac{-3+\sqrt{34}}{2}
$

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